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43054050651 = 331634537259
BaseRepresentation
bin101000000110001110…
…001010110101011011
311010010111210101101120
4220012032022311123
51201133314110101
631440113420323
73052630251363
oct500616126533
9133114711346
1043054050651
1117293986547
12841686a6a3
1340a1a0cb21
1421260439a3
1511beba5b36
hexa0638ad5b

43054050651 has 8 divisors (see below), whose sum is σ = 57423562560. Its totient is φ = 28693619592.

The previous prime is 43054050631. The next prime is 43054050653. The reversal of 43054050651 is 15605045034.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 43054050651 - 218 = 43053788507 is a prime.

It is a super-3 number, since 3×430540506513 (a number of 33 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (43054050653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2259141 + ... + 2278118.

It is an arithmetic number, because the mean of its divisors is an integer number (7177945320).

Almost surely, 243054050651 is an apocalyptic number.

43054050651 is a deficient number, since it is larger than the sum of its proper divisors (14369511909).

43054050651 is a wasteful number, since it uses less digits than its factorization.

43054050651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4540425.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 43054050651 its reverse (15605045034), we get a palindrome (58659095685).

The spelling of 43054050651 in words is "forty-three billion, fifty-four million, fifty thousand, six hundred fifty-one".

Divisors: 1 3 3163 9489 4537259 13611777 14351350217 43054050651