Base | Representation |
---|---|
bin | 1100100010011100011… |
… | …10000110010101010011 |
3 | 1112011222211020012010121 |
4 | 12101032032012111103 |
5 | 24024244104022103 |
6 | 525524433011111 |
7 | 43060564330366 |
oct | 6211616062523 |
9 | 1464884205117 |
10 | 430809048403 |
11 | 156783527478 |
12 | 6b5b10b3a97 |
13 | 318185039b6 |
14 | 16bcbc500dd |
15 | b3165856bd |
hex | 644e386553 |
430809048403 has 2 divisors, whose sum is σ = 430809048404. Its totient is φ = 430809048402.
The previous prime is 430809048401. The next prime is 430809048421. The reversal of 430809048403 is 304840908034.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 430809048403 - 21 = 430809048401 is a prime.
Together with 430809048401, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 430809048403.
It is not a weakly prime, because it can be changed into another prime (430809048401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215404524201 + 215404524202.
It is an arithmetic number, because the mean of its divisors is an integer number (215404524202).
Almost surely, 2430809048403 is an apocalyptic number.
430809048403 is a deficient number, since it is larger than the sum of its proper divisors (1).
430809048403 is an equidigital number, since it uses as much as digits as its factorization.
430809048403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 43.
The spelling of 430809048403 in words is "four hundred thirty billion, eight hundred nine million, forty-eight thousand, four hundred three".
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