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430981689401 is a prime number
BaseRepresentation
bin1100100010110001000…
…00101011000000111001
31112012102212002021001122
412101120200223000321
524030122303030101
6525553521155025
743065061626044
oct6213040530071
91465385067048
10430981689401
11156861a2318a
126b63aa8ba75
13318451cc133
1416c06b4dc5b
15b3267d851b
hex645882b039

430981689401 has 2 divisors, whose sum is σ = 430981689402. Its totient is φ = 430981689400.

The previous prime is 430981689373. The next prime is 430981689403. The reversal of 430981689401 is 104986189034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 428731610176 + 2250079225 = 654776^2 + 47435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-430981689401 is a prime.

Together with 430981689403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (430981689403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215490844700 + 215490844701.

It is an arithmetic number, because the mean of its divisors is an integer number (215490844701).

Almost surely, 2430981689401 is an apocalyptic number.

It is an amenable number.

430981689401 is a deficient number, since it is larger than the sum of its proper divisors (1).

430981689401 is an equidigital number, since it uses as much as digits as its factorization.

430981689401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1492992, while the sum is 53.

The spelling of 430981689401 in words is "four hundred thirty billion, nine hundred eighty-one million, six hundred eighty-nine thousand, four hundred one".