Base | Representation |
---|---|
bin | 111110101110000111001… |
… | …011110001111011000001 |
3 | 120021001011200120200002001 |
4 | 332232013023301323001 |
5 | 1031104111233210423 |
6 | 13100013014224001 |
7 | 623252540205304 |
oct | 76560713617301 |
9 | 16231150520061 |
10 | 4310120210113 |
11 | 1411a03548583 |
12 | 5973b6655001 |
13 | 25359a4b3243 |
14 | 10c87a576b3b |
15 | 771b1d6ecad |
hex | 3eb872f1ec1 |
4310120210113 has 2 divisors, whose sum is σ = 4310120210114. Its totient is φ = 4310120210112.
The previous prime is 4310120210111. The next prime is 4310120210177. The reversal of 4310120210113 is 3110120210134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3772696329649 + 537423880464 = 1942343^2 + 733092^2 .
It is a cyclic number.
It is not a de Polignac number, because 4310120210113 - 21 = 4310120210111 is a prime.
Together with 4310120210111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4310120210111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155060105056 + 2155060105057.
It is an arithmetic number, because the mean of its divisors is an integer number (2155060105057).
Almost surely, 24310120210113 is an apocalyptic number.
It is an amenable number.
4310120210113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4310120210113 is an equidigital number, since it uses as much as digits as its factorization.
4310120210113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 4310120210113 its reverse (3110120210134), we get a palindrome (7420240420247).
The spelling of 4310120210113 in words is "four trillion, three hundred ten billion, one hundred twenty million, two hundred ten thousand, one hundred thirteen".
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