431012113433 has 4 divisors (see below), whose sum is σ = 470195032848. Its totient is φ = 391829194020.

The previous prime is 431012113417. The next prime is 431012113447. The reversal of 431012113433 is 334311210134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 431012113433 - 2⁴ = 431012113417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (431012113933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19591459691 + ... + 19591459712.

It is an arithmetic number, because the mean of its divisors is an integer number (117548758212).

Almost surely, 2^431012113433 is an apocalyptic number.

It is an amenable number.

431012113433 is a deficient number, since it is larger than the sum of its proper divisors (39182919415).

431012113433 is a wasteful number, since it uses less digits than its factorization.

431012113433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39182919414.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 431012113433 its reverse (334311210134), we get a palindrome (765323323567).

It can be divided in two parts, 431012 and 113433, that added together give a palindrome (544445).

The spelling of 431012113433 in words is "four hundred thirty-one billion, twelve million, one hundred thirteen thousand, four hundred thirty-three".