Base | Representation |
---|---|
bin | 101000001001001001… |
… | …000000101101111101 |
3 | 11010020220221210121202 |
4 | 220021021000231331 |
5 | 1201233333431031 |
6 | 31445023305245 |
7 | 3054063465623 |
oct | 501111005575 |
9 | 133226853552 |
10 | 43103030141 |
11 | 1730959a566 |
12 | 842b14b225 |
13 | 40abbcb882 |
14 | 212c753513 |
15 | 11c412d2cb |
hex | a09240b7d |
43103030141 has 4 divisors (see below), whose sum is σ = 43255337952. Its totient is φ = 42950722332.
The previous prime is 43103030119. The next prime is 43103030143. The reversal of 43103030141 is 14103030134.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14103030134 = 2 ⋅7051515067.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43103030141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43103030143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76153481 + ... + 76154046.
It is an arithmetic number, because the mean of its divisors is an integer number (10813834488).
Almost surely, 243103030141 is an apocalyptic number.
It is an amenable number.
43103030141 is a deficient number, since it is larger than the sum of its proper divisors (152307811).
43103030141 is a wasteful number, since it uses less digits than its factorization.
43103030141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 152307810.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 43103030141 its reverse (14103030134), we get a palindrome (57206060275).
The spelling of 43103030141 in words is "forty-three billion, one hundred three million, thirty thousand, one hundred forty-one".
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