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43103321341 is a prime number
BaseRepresentation
bin101000001001001010…
…000111110011111101
311010020221111121001221
4220021022013303331
51201233422240331
631445033433341
73054066120613
oct501112076375
9133227447057
1043103321341
1117309779323
12842b26b851
1340abca1292
14212c7cb6b3
1511c4189711
hexa09287cfd

43103321341 has 2 divisors, whose sum is σ = 43103321342. Its totient is φ = 43103321340.

The previous prime is 43103321293. The next prime is 43103321399. The reversal of 43103321341 is 14312330134.

43103321341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23961492025 + 19141829316 = 154795^2 + 138354^2 .

It is a cyclic number.

It is not a de Polignac number, because 43103321341 - 217 = 43103190269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43103321141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21551660670 + 21551660671.

It is an arithmetic number, because the mean of its divisors is an integer number (21551660671).

Almost surely, 243103321341 is an apocalyptic number.

It is an amenable number.

43103321341 is a deficient number, since it is larger than the sum of its proper divisors (1).

43103321341 is an equidigital number, since it uses as much as digits as its factorization.

43103321341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 43103321341 its reverse (14312330134), we get a palindrome (57415651475).

The spelling of 43103321341 in words is "forty-three billion, one hundred three million, three hundred twenty-one thousand, three hundred forty-one".