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4310402110113 = 311229756864713
BaseRepresentation
bin111110101110010111111…
…111001001001010100001
3120021001220100000200011210
4332232113333021022201
51031110200420010423
613100101004300333
7623262532261221
oct76562777111241
916231810020153
104310402110113
11141203868a190
12597474b416a9
13253613a14688
1410c8a5b98081
15771cb9a5b93
hex3eb97fc92a1

4310402110113 has 16 divisors (see below), whose sum is σ = 6272405413056. Its totient is φ = 2611227575040.

The previous prime is 4310402110033. The next prime is 4310402110139. The reversal of 4310402110113 is 3110112040134.

It is not a de Polignac number, because 4310402110113 - 229 = 4309865239201 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4310402110113.

It is not an unprimeable number, because it can be changed into a prime (4310402110813) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28356556 + ... + 28508157.

It is an arithmetic number, because the mean of its divisors is an integer number (392025338316).

Almost surely, 24310402110113 is an apocalyptic number.

It is an amenable number.

4310402110113 is a deficient number, since it is larger than the sum of its proper divisors (1962003302943).

4310402110113 is a wasteful number, since it uses less digits than its factorization.

4310402110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56867024.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 4310402110113 its reverse (3110112040134), we get a palindrome (7420514150247).

The spelling of 4310402110113 in words is "four trillion, three hundred ten billion, four hundred two million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3 11 33 2297 6891 25267 75801 56864713 170594139 625511843 1876535529 130618245761 391854737283 1436800703371 4310402110113