Base | Representation |
---|---|
bin | 110001000000001110110010… |
… | …0000010000001101100110001 |
3 | 2002112012001100201000220202221 |
4 | 1202000131210002001230301 |
5 | 422444131014041041423 |
6 | 4124425103005241041 |
7 | 156535430326022350 |
oct | 14200354402015461 |
9 | 2075161321026687 |
10 | 431040301112113 |
11 | 11538518a864670 |
12 | 404165b8863181 |
13 | 15668c06505124 |
14 | 78626675cb997 |
15 | 34c75327d3e5d |
hex | 1880764081b31 |
431040301112113 has 16 divisors (see below), whose sum is σ = 537763269206016. Its totient is φ = 335649075362640.
The previous prime is 431040301112087. The next prime is 431040301112167. The reversal of 431040301112113 is 311211103040134.
It is a cyclic number.
It is not a de Polignac number, because 431040301112113 - 241 = 428841277856561 is a prime.
It is not an unprimeable number, because it can be changed into a prime (431040301122113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1887251281 + ... + 1887479662.
It is an arithmetic number, because the mean of its divisors is an integer number (33610204325376).
Almost surely, 2431040301112113 is an apocalyptic number.
It is an amenable number.
431040301112113 is a deficient number, since it is larger than the sum of its proper divisors (106722968093903).
431040301112113 is a wasteful number, since it uses less digits than its factorization.
431040301112113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3774732444.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 431040301112113 its reverse (311211103040134), we get a palindrome (742251404152247).
The spelling of 431040301112113 in words is "four hundred thirty-one trillion, forty billion, three hundred one million, one hundred twelve thousand, one hundred thirteen".
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