Base | Representation |
---|---|
bin | 110001000000001110110111… |
… | …1111001001001101101101011 |
3 | 2002112012001212120111011121211 |
4 | 1202000131233321021231223 |
5 | 422444131421012042420 |
6 | 4124425134434413551 |
7 | 156535435263343546 |
oct | 14200355771115553 |
9 | 2075161776434554 |
10 | 431040500112235 |
11 | 115385282124382 |
12 | 404166534312b7 |
13 | 15668c387cc290 |
14 | 7862685bcd85d |
15 | 34c7544ee1e5a |
hex | 188076fe49b6b |
431040500112235 has 16 divisors (see below), whose sum is σ = 575005887993600. Its totient is φ = 308038868565120.
The previous prime is 431040500112143. The next prime is 431040500112259. The reversal of 431040500112235 is 532211005040134.
It is not a de Polignac number, because 431040500112235 - 219 = 431040499587947 is a prime.
It is a super-2 number, since 2×4310405001122352 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 431040500112197 and 431040500112206.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106957938460 + ... + 106957942489.
It is an arithmetic number, because the mean of its divisors is an integer number (35937867999600).
Almost surely, 2431040500112235 is an apocalyptic number.
431040500112235 is a deficient number, since it is larger than the sum of its proper divisors (143965387881365).
431040500112235 is a wasteful number, since it uses less digits than its factorization.
431040500112235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213915880998.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 431040500112235 its reverse (532211005040134), we get a palindrome (963251505152369).
The spelling of 431040500112235 in words is "four hundred thirty-one trillion, forty billion, five hundred million, one hundred twelve thousand, two hundred thirty-five".
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