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43104315353 = 113918574123
BaseRepresentation
bin101000001001001101…
…111010011111011001
311010021000101002121012
4220021031322133121
51201234201042403
631445111023305
73054110430611
oct501115723731
9133230332535
1043104315353
111730a298120
12842b66ab35
1340ac25b858
14212c9a9a41
1511c42d3ed8
hexa0937a7d9

43104315353 has 4 divisors (see below), whose sum is σ = 47022889488. Its totient is φ = 39185741220.

The previous prime is 43104315323. The next prime is 43104315361. The reversal of 43104315353 is 35351340134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43104315353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43104315323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1959287051 + ... + 1959287072.

It is an arithmetic number, because the mean of its divisors is an integer number (11755722372).

Almost surely, 243104315353 is an apocalyptic number.

It is an amenable number.

43104315353 is a deficient number, since it is larger than the sum of its proper divisors (3918574135).

43104315353 is a wasteful number, since it uses less digits than its factorization.

43104315353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3918574134.

The product of its (nonzero) digits is 32400, while the sum is 32.

Adding to 43104315353 its reverse (35351340134), we get a palindrome (78455655487).

The spelling of 43104315353 in words is "forty-three billion, one hundred four million, three hundred fifteen thousand, three hundred fifty-three".

Divisors: 1 11 3918574123 43104315353