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43104414113 = 157372739049
BaseRepresentation
bin101000001001001110…
…010010100110100001
311010021000120010001222
4220021032102212201
51201234212222423
631445113104425
73054111321545
oct501116224641
9133230503058
1043104414113
111730a355342
12842b6b8115
1340ac2947a7
14212c9d3a25
1511c43033c8
hexa093929a1

43104414113 has 4 divisors (see below), whose sum is σ = 43107168900. Its totient is φ = 43101659328.

The previous prime is 43104414097. The next prime is 43104414121. The reversal of 43104414113 is 31141440134.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 38865362449 + 4239051664 = 197143^2 + 65108^2 .

It is a cyclic number.

It is not a de Polignac number, because 43104414113 - 24 = 43104414097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43101414113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353788 + ... + 1385261.

It is an arithmetic number, because the mean of its divisors is an integer number (10776792225).

Almost surely, 243104414113 is an apocalyptic number.

It is an amenable number.

43104414113 is a deficient number, since it is larger than the sum of its proper divisors (2754787).

43104414113 is a wasteful number, since it uses less digits than its factorization.

43104414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2754786.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 43104414113 its reverse (31141440134), we get a palindrome (74245854247).

The spelling of 43104414113 in words is "forty-three billion, one hundred four million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 15737 2739049 43104414113