Base | Representation |
---|---|
bin | 101000001001001110… |
… | …010111001101110011 |
3 | 11010021000121001222220 |
4 | 220021032113031303 |
5 | 1201234213324021 |
6 | 31445113332123 |
7 | 3054111430623 |
oct | 501116271563 |
9 | 133230531886 |
10 | 43104433011 |
11 | 1730a368562 |
12 | 842b707043 |
13 | 40ac2a0283 |
14 | 212c9da883 |
15 | 11c4308cc6 |
hex | a09397373 |
43104433011 has 64 divisors (see below), whose sum is σ = 68403916800. Its totient is φ = 23940403200.
The previous prime is 43104432961. The next prime is 43104433013. The reversal of 43104433011 is 11033440134.
43104433011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 43104433011 - 213 = 43104424819 is a prime.
It is a super-2 number, since 2×431044330112 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (43104433013) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 846391 + ... + 895871.
It is an arithmetic number, because the mean of its divisors is an integer number (1068811200).
Almost surely, 243104433011 is an apocalyptic number.
43104433011 is a deficient number, since it is larger than the sum of its proper divisors (25299483789).
43104433011 is a wasteful number, since it uses less digits than its factorization.
43104433011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49580.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 43104433011 its reverse (11033440134), we get a palindrome (54137873145).
The spelling of 43104433011 in words is "forty-three billion, one hundred four million, four hundred thirty-three thousand, eleven".
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