Base | Representation |
---|---|
bin | 1100100010111001101… |
… | …01110100011110100011 |
3 | 1112012121220210101202112 |
4 | 12101130311310132203 |
5 | 24030244402421201 |
6 | 530005034305535 |
7 | 43066633311254 |
oct | 6213465643643 |
9 | 1465556711675 |
10 | 431054342051 |
11 | 156899a361a3 |
12 | 6b65b2882ab |
13 | 31857289178 |
14 | 16c12662b2b |
15 | b32cd8a0bb |
hex | 645cd747a3 |
431054342051 has 2 divisors, whose sum is σ = 431054342052. Its totient is φ = 431054342050.
The previous prime is 431054341999. The next prime is 431054342053. The reversal of 431054342051 is 150243450134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 431054342051 - 222 = 431050147747 is a prime.
It is a Sophie Germain prime.
Together with 431054342053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 431054341999 and 431054342017.
It is not a weakly prime, because it can be changed into another prime (431054342053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215527171025 + 215527171026.
It is an arithmetic number, because the mean of its divisors is an integer number (215527171026).
Almost surely, 2431054342051 is an apocalyptic number.
431054342051 is a deficient number, since it is larger than the sum of its proper divisors (1).
431054342051 is an equidigital number, since it uses as much as digits as its factorization.
431054342051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 431054342051 its reverse (150243450134), we get a palindrome (581297792185).
The spelling of 431054342051 in words is "four hundred thirty-one billion, fifty-four million, three hundred forty-two thousand, fifty-one".
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