Base | Representation |
---|---|
bin | 1100100011000010000… |
… | …00000101011111000101 |
3 | 1112012210210010121022121 |
4 | 12101201000011133011 |
5 | 24030420240021041 |
6 | 530020010325541 |
7 | 43101441512566 |
oct | 6214100053705 |
9 | 1465723117277 |
10 | 431124142021 |
11 | 15692537aa21 |
12 | 6b67a7298b1 |
13 | 31868887921 |
14 | 16c1ba3216d |
15 | b3340767d1 |
hex | 64610057c5 |
431124142021 has 2 divisors, whose sum is σ = 431124142022. Its totient is φ = 431124142020.
The previous prime is 431124142013. The next prime is 431124142049. The reversal of 431124142021 is 120241421134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 349859237121 + 81264904900 = 591489^2 + 285070^2 .
It is a cyclic number.
It is not a de Polignac number, because 431124142021 - 23 = 431124142013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (431124142621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215562071010 + 215562071011.
It is an arithmetic number, because the mean of its divisors is an integer number (215562071011).
Almost surely, 2431124142021 is an apocalyptic number.
It is an amenable number.
431124142021 is a deficient number, since it is larger than the sum of its proper divisors (1).
431124142021 is an equidigital number, since it uses as much as digits as its factorization.
431124142021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 431124142021 its reverse (120241421134), we get a palindrome (551365563155).
The spelling of 431124142021 in words is "four hundred thirty-one billion, one hundred twenty-four million, one hundred forty-two thousand, twenty-one".
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