Base | Representation |
---|---|
bin | 101000001001110010… |
… | …111110010000101001 |
3 | 11010021200122122202102 |
4 | 220021302332100221 |
5 | 1201244142430441 |
6 | 31450055143145 |
7 | 3054256131551 |
oct | 501162762051 |
9 | 133250578672 |
10 | 43114030121 |
11 | 17314822a58 |
12 | 8432974ab5 |
13 | 40b1280636 |
14 | 212ddb8161 |
15 | 11c50a269b |
hex | a09cbe429 |
43114030121 has 2 divisors, whose sum is σ = 43114030122. Its totient is φ = 43114030120.
The previous prime is 43114030117. The next prime is 43114030133. The reversal of 43114030121 is 12103041134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23845536400 + 19268493721 = 154420^2 + 138811^2 .
It is a cyclic number.
It is not a de Polignac number, because 43114030121 - 22 = 43114030117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43114030093 and 43114030102.
It is not a weakly prime, because it can be changed into another prime (43114030111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21557015060 + 21557015061.
It is an arithmetic number, because the mean of its divisors is an integer number (21557015061).
Almost surely, 243114030121 is an apocalyptic number.
It is an amenable number.
43114030121 is a deficient number, since it is larger than the sum of its proper divisors (1).
43114030121 is an equidigital number, since it uses as much as digits as its factorization.
43114030121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 43114030121 its reverse (12103041134), we get a palindrome (55217071255).
The spelling of 43114030121 in words is "forty-three billion, one hundred fourteen million, thirty thousand, one hundred twenty-one".
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