Base | Representation |
---|---|
bin | 1100100011000100000… |
… | …00011011111100000011 |
3 | 1112012211221212122111010 |
4 | 12101202000123330003 |
5 | 24030434044324303 |
6 | 530021412052003 |
7 | 43102035062100 |
oct | 6214200337403 |
9 | 1465757778433 |
10 | 431141011203 |
11 | 156933951aa1 |
12 | 6b684304003 |
13 | 3186c212ca6 |
14 | 16c1dd83aa7 |
15 | b3357a9c03 |
hex | 646201bf03 |
431141011203 has 24 divisors (see below), whose sum is σ = 668733248592. Its totient is φ = 246357177024.
The previous prime is 431141011199. The next prime is 431141011247. The reversal of 431141011203 is 302110141134.
It is not a de Polignac number, because 431141011203 - 22 = 431141011199 is a prime.
It is a super-2 number, since 2×4311410112032 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 431141011203.
It is not an unprimeable number, because it can be changed into a prime (431141011703) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7461901 + ... + 7519457.
It is an arithmetic number, because the mean of its divisors is an integer number (27863885358).
Almost surely, 2431141011203 is an apocalyptic number.
431141011203 is a deficient number, since it is larger than the sum of its proper divisors (237592237389).
431141011203 is a wasteful number, since it uses less digits than its factorization.
431141011203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108531 (or 108524 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 431141011203 its reverse (302110141134), we get a palindrome (733251152337).
The spelling of 431141011203 in words is "four hundred thirty-one billion, one hundred forty-one million, eleven thousand, two hundred three".
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