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431141145520999 is a prime number
BaseRepresentation
bin110001000000111101101111…
…0110100111010101101100111
32002112112200122201120200020211
41202001323132310322231213
5423002304031223132444
64124543301415040251
7156545630335244344
oct14201733664725547
92075480581520224
10431141145520999
11115413a29902651
1240432061370087
1315675587c45ca4
1478674b28577cb
1534c9e85c18c34
hex1881eded3ab67

431141145520999 has 2 divisors, whose sum is σ = 431141145521000. Its totient is φ = 431141145520998.

The previous prime is 431141145520867. The next prime is 431141145521113. The reversal of 431141145520999 is 999025541141134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431141145520999 - 221 = 431141143423847 is a prime.

It is a super-2 number, since 2×4311411455209992 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431141145520699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215570572760499 + 215570572760500.

It is an arithmetic number, because the mean of its divisors is an integer number (215570572760500).

Almost surely, 2431141145520999 is an apocalyptic number.

431141145520999 is a deficient number, since it is larger than the sum of its proper divisors (1).

431141145520999 is an equidigital number, since it uses as much as digits as its factorization.

431141145520999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 58.

The spelling of 431141145520999 in words is "four hundred thirty-one trillion, one hundred forty-one billion, one hundred forty-five million, five hundred twenty thousand, nine hundred ninety-nine".