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431141312002 = 2215570656001
BaseRepresentation
bin1100100011000100000…
…01100101011000000010
31112012211222102221002211
412101202001211120002
524030434133441002
6530021422332334
743102040454052
oct6214201453002
91465758387084
10431141312002
11156934037a95
126b68442a0aa
133186c2b9b8b
1416c20021562
15b335818dd7
hex6462065602

431141312002 has 4 divisors (see below), whose sum is σ = 646711968006. Its totient is φ = 215570656000.

The previous prime is 431141311987. The next prime is 431141312009. The reversal of 431141312002 is 200213141134.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200213141134 = 2100106570567.

It can be written as a sum of positive squares in only one way, i.e., 333391914801 + 97749397201 = 577401^2 + 312649^2 .

It is not an unprimeable number, because it can be changed into a prime (431141312009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107785327999 + ... + 107785328002.

Almost surely, 2431141312002 is an apocalyptic number.

431141312002 is a deficient number, since it is larger than the sum of its proper divisors (215570656004).

431141312002 is a wasteful number, since it uses less digits than its factorization.

431141312002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215570656003.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 431141312002 its reverse (200213141134), we get a palindrome (631354453136).

The spelling of 431141312002 in words is "four hundred thirty-one billion, one hundred forty-one million, three hundred twelve thousand, two".

Divisors: 1 2 215570656001 431141312002