Base | Representation |
---|---|
bin | 1100100011000100000… |
… | …01100101011000000010 |
3 | 1112012211222102221002211 |
4 | 12101202001211120002 |
5 | 24030434133441002 |
6 | 530021422332334 |
7 | 43102040454052 |
oct | 6214201453002 |
9 | 1465758387084 |
10 | 431141312002 |
11 | 156934037a95 |
12 | 6b68442a0aa |
13 | 3186c2b9b8b |
14 | 16c20021562 |
15 | b335818dd7 |
hex | 6462065602 |
431141312002 has 4 divisors (see below), whose sum is σ = 646711968006. Its totient is φ = 215570656000.
The previous prime is 431141311987. The next prime is 431141312009. The reversal of 431141312002 is 200213141134.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200213141134 = 2 ⋅100106570567.
It can be written as a sum of positive squares in only one way, i.e., 333391914801 + 97749397201 = 577401^2 + 312649^2 .
It is not an unprimeable number, because it can be changed into a prime (431141312009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107785327999 + ... + 107785328002.
Almost surely, 2431141312002 is an apocalyptic number.
431141312002 is a deficient number, since it is larger than the sum of its proper divisors (215570656004).
431141312002 is a wasteful number, since it uses less digits than its factorization.
431141312002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 215570656003.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 431141312002 its reverse (200213141134), we get a palindrome (631354453136).
The spelling of 431141312002 in words is "four hundred thirty-one billion, one hundred forty-one million, three hundred twelve thousand, two".
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