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431143112431 is a prime number
BaseRepresentation
bin1100100011000100010…
…00011100111011101111
31112012212002211101211101
412101202020130323233
524030440114044211
6530021525103531
743102061663113
oct6214210347357
91465762741741
10431143112431
11156935057749
126b684b57ba7
133186c79a515
1416c2036d743
15b335a725c1
hex646221ceef

431143112431 has 2 divisors, whose sum is σ = 431143112432. Its totient is φ = 431143112430.

The previous prime is 431143112381. The next prime is 431143112453. The reversal of 431143112431 is 134211341134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431143112431 - 27 = 431143112303 is a prime.

It is a super-2 number, since 2×4311431124312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 431143112431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431143152431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215571556215 + 215571556216.

It is an arithmetic number, because the mean of its divisors is an integer number (215571556216).

Almost surely, 2431143112431 is an apocalyptic number.

431143112431 is a deficient number, since it is larger than the sum of its proper divisors (1).

431143112431 is an equidigital number, since it uses as much as digits as its factorization.

431143112431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456, while the sum is 28.

Adding to 431143112431 its reverse (134211341134), we get a palindrome (565354453565).

The spelling of 431143112431 in words is "four hundred thirty-one billion, one hundred forty-three million, one hundred twelve thousand, four hundred thirty-one".