431201234041 has 4 divisors (see below), whose sum is σ = 456566012532. Its totient is φ = 405836455552.

The previous prime is 431201234017. The next prime is 431201234069. The reversal of 431201234041 is 140432102134.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 361176960400 + 70024273641 = 600980^2 + 264621^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-431201234041 is a prime.

It is a super-3 number, since 3×431201234041³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 431201233997 and 431201234015.

It is not an unprimeable number, because it can be changed into a prime (431201234011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12682389220 + ... + 12682389253.

It is an arithmetic number, because the mean of its divisors is an integer number (114141503133).

Almost surely, 2^431201234041 is an apocalyptic number.

It is an amenable number.

431201234041 is a deficient number, since it is larger than the sum of its proper divisors (25364778491).

431201234041 is a wasteful number, since it uses less digits than its factorization.

431201234041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25364778490.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 431201234041 its reverse (140432102134), we get a palindrome (571633336175).

The spelling of 431201234041 in words is "four hundred thirty-one billion, two hundred one million, two hundred thirty-four thousand, forty-one".