Base | Representation |
---|---|
bin | 10011100110111111010111… |
… | …01101011100101100110110 |
3 | 12122200100011210000001202122 |
4 | 21303133223231130230312 |
5 | 21122444034044304332 |
6 | 231413324010435542 |
7 | 12040253554636514 |
oct | 1163375355345466 |
9 | 178610153001678 |
10 | 43121131244342 |
11 | 12815629470548 |
12 | 4a051b7732bb2 |
13 | 1b0a3c7781b78 |
14 | a91106a6b4b4 |
15 | 4eba2d8bec12 |
hex | 2737ebb5cb36 |
43121131244342 has 4 divisors (see below), whose sum is σ = 64681696866516. Its totient is φ = 21560565622170.
The previous prime is 43121131244341. The next prime is 43121131244363. The reversal of 43121131244342 is 24344213112134.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43121131244341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10780282811084 + ... + 10780282811087.
It is an arithmetic number, because the mean of its divisors is an integer number (16170424216629).
Almost surely, 243121131244342 is an apocalyptic number.
43121131244342 is a deficient number, since it is larger than the sum of its proper divisors (21560565622174).
43121131244342 is a wasteful number, since it uses less digits than its factorization.
43121131244342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21560565622173.
The product of its digits is 55296, while the sum is 35.
Adding to 43121131244342 its reverse (24344213112134), we get a palindrome (67465344356476).
The spelling of 43121131244342 in words is "forty-three trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred forty-four thousand, three hundred forty-two".
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