Base | Representation |
---|---|
bin | 111110101111111111000… |
… | …010100010000111100001 |
3 | 120021020100211100000120112 |
4 | 332233333002202013201 |
5 | 1031122221022131001 |
6 | 13100544325421105 |
7 | 623353425114143 |
oct | 76577702420741 |
9 | 16236324300515 |
10 | 4312131052001 |
11 | 141284561a883 |
12 | 597877b6a795 |
13 | 25382ac85406 |
14 | 10c9cb654c93 |
15 | 7727d674cbb |
hex | 3ebff0a21e1 |
4312131052001 has 2 divisors, whose sum is σ = 4312131052002. Its totient is φ = 4312131052000.
The previous prime is 4312131051983. The next prime is 4312131052007. The reversal of 4312131052001 is 1002501312134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4118707891600 + 193423160401 = 2029460^2 + 439799^2 .
It is a cyclic number.
It is not a de Polignac number, because 4312131052001 - 210 = 4312131050977 is a prime.
It is a super-2 number, since 2×43121310520012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4312131052007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156065526000 + 2156065526001.
It is an arithmetic number, because the mean of its divisors is an integer number (2156065526001).
Almost surely, 24312131052001 is an apocalyptic number.
It is an amenable number.
4312131052001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312131052001 is an equidigital number, since it uses as much as digits as its factorization.
4312131052001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 4312131052001 its reverse (1002501312134), we get a palindrome (5314632364135).
The spelling of 4312131052001 in words is "four trillion, three hundred twelve billion, one hundred thirty-one million, fifty-two thousand, one".
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