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43122144031 is a prime number
BaseRepresentation
bin101000001010010001…
…111011001100011111
311010022020220212221121
4220022101323030133
51201303232102111
631450545111411
73054415114351
oct501221731437
9133266825847
1043122144031
111731936506a
128435628567
1340b2b61875
1421310cb0d1
1511c5b56871
hexa0a47b31f

43122144031 has 2 divisors, whose sum is σ = 43122144032. Its totient is φ = 43122144030.

The previous prime is 43122144017. The next prime is 43122144041. The reversal of 43122144031 is 13044122134.

43122144031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43122144031 - 27 = 43122143903 is a prime.

It is a super-2 number, since 2×431221440312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43122143987 and 43122144005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43122144001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21561072015 + 21561072016.

It is an arithmetic number, because the mean of its divisors is an integer number (21561072016).

Almost surely, 243122144031 is an apocalyptic number.

43122144031 is a deficient number, since it is larger than the sum of its proper divisors (1).

43122144031 is an equidigital number, since it uses as much as digits as its factorization.

43122144031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 43122144031 its reverse (13044122134), we get a palindrome (56166266165).

The spelling of 43122144031 in words is "forty-three billion, one hundred twenty-two million, one hundred forty-four thousand, thirty-one".