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43122314434 = 221561157217
BaseRepresentation
bin101000001010010010…
…100100110011000010
311010022021020112200211
4220022102210303002
51201303303030214
631450552504334
73054416424223
oct501222446302
9133267215624
1043122314434
11173194710a1
1284356ab0aa
1340b2bc12b4
14213113324a
1511c5b8c0c4
hexa0a4a4cc2

43122314434 has 4 divisors (see below), whose sum is σ = 64683471654. Its totient is φ = 21561157216.

The previous prime is 43122314429. The next prime is 43122314437. The reversal of 43122314434 is 43441322134.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 31738491409 + 11383823025 = 178153^2 + 106695^2 .

It is a junction number, because it is equal to n+sod(n) for n = 43122314396 and 43122314405.

It is not an unprimeable number, because it can be changed into a prime (43122314437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10780578607 + ... + 10780578610.

Almost surely, 243122314434 is an apocalyptic number.

43122314434 is a deficient number, since it is larger than the sum of its proper divisors (21561157220).

43122314434 is a wasteful number, since it uses less digits than its factorization.

43122314434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21561157219.

The product of its digits is 27648, while the sum is 31.

Adding to 43122314434 its reverse (43441322134), we get a palindrome (86563636568).

The spelling of 43122314434 in words is "forty-three billion, one hundred twenty-two million, three hundred fourteen thousand, four hundred thirty-four".

Divisors: 1 2 21561157217 43122314434