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4312551210131 is a prime number
BaseRepresentation
bin111110110000011000000…
…101010011110010010011
3120021021110002221021011202
4332300120011103302103
51031124101102211011
613101054135101415
7623400016314023
oct76603005236223
916237402837152
104312551210131
111412a408038aa
1259797481186b
132538970340a8
1410ca2b385a83
15772a54bb23b
hex3ec18153c93

4312551210131 has 2 divisors, whose sum is σ = 4312551210132. Its totient is φ = 4312551210130.

The previous prime is 4312551210103. The next prime is 4312551210179. The reversal of 4312551210131 is 1310121552134.

It is a happy number.

4312551210131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4312551210131 - 26 = 4312551210067 is a prime.

It is a super-2 number, since 2×43125512101312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4312551210094 and 4312551210103.

It is not a weakly prime, because it can be changed into another prime (4312551210431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156275605065 + 2156275605066.

It is an arithmetic number, because the mean of its divisors is an integer number (2156275605066).

Almost surely, 24312551210131 is an apocalyptic number.

4312551210131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312551210131 is an equidigital number, since it uses as much as digits as its factorization.

4312551210131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 4312551210131 its reverse (1310121552134), we get a palindrome (5622672762265).

The spelling of 4312551210131 in words is "four trillion, three hundred twelve billion, five hundred fifty-one million, two hundred ten thousand, one hundred thirty-one".