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431255343552133 is a prime number
BaseRepresentation
bin110001000001110010111010…
…1100011110101011010000101
32002112221121102101022201201111
41202003211311203311122011
5423011141420422132013
64125111545251125021
7156560112303425542
oct14203456543653205
92075847371281644
10431255343552133
111154584006a4681
1240450211ba3771
13156832870ac689
14786cc273bdbc9
1534cce1b65273d
hex18839758f5685

431255343552133 has 2 divisors, whose sum is σ = 431255343552134. Its totient is φ = 431255343552132.

The previous prime is 431255343552107. The next prime is 431255343552151. The reversal of 431255343552133 is 331255343552134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 288186545219364 + 143068798332769 = 16976058^2 + 11961137^2 .

It is a cyclic number.

It is not a de Polignac number, because 431255343552133 - 29 = 431255343551621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431255343052133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215627671776066 + 215627671776067.

It is an arithmetic number, because the mean of its divisors is an integer number (215627671776067).

Almost surely, 2431255343552133 is an apocalyptic number.

It is an amenable number.

431255343552133 is a deficient number, since it is larger than the sum of its proper divisors (1).

431255343552133 is an equidigital number, since it uses as much as digits as its factorization.

431255343552133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720000, while the sum is 49.

Subtracting from 431255343552133 its reverse (331255343552134), we obtain a palindrome (99999999999999).

The spelling of 431255343552133 in words is "four hundred thirty-one trillion, two hundred fifty-five billion, three hundred forty-three million, five hundred fifty-two thousand, one hundred thirty-three".