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4312918254053 is a prime number
BaseRepresentation
bin111110110000101101111…
…101011110000111100101
3120021022101200121000210002
4332300231331132013211
51031130324033112203
613101154410111045
7623412064165643
oct76605575360745
916238350530702
104312918254053
111413109a0a392
12597a5771b485
132539250a7046
1410ca6400c193
15772c781ed88
hex3ec2df5e1e5

4312918254053 has 2 divisors, whose sum is σ = 4312918254054. Its totient is φ = 4312918254052.

The previous prime is 4312918253977. The next prime is 4312918254061. The reversal of 4312918254053 is 3504528192134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2843833658689 + 1469084595364 = 1686367^2 + 1212058^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312918254053 - 212 = 4312918249957 is a prime.

It is a super-2 number, since 2×43129182540532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4312918253989 and 4312918254007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4312918254553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156459127026 + 2156459127027.

It is an arithmetic number, because the mean of its divisors is an integer number (2156459127027).

Almost surely, 24312918254053 is an apocalyptic number.

It is an amenable number.

4312918254053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312918254053 is an equidigital number, since it uses as much as digits as its factorization.

4312918254053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 47.

The spelling of 4312918254053 in words is "four trillion, three hundred twelve billion, nine hundred eighteen million, two hundred fifty-four thousand, fifty-three".