Search a number
-
+
4313003404001 = 5381377422717
BaseRepresentation
bin111110110000110011000…
…010010010101011100001
3120021022121121211002112212
4332300303002102223201
51031131012332412001
613101211051131505
7623414150021345
oct76606302225341
916238547732485
104313003404001
111413152a88846
12597a80143b95
1325393991b526
1410ca71455625
15772d003e7bb
hex3ec33092ae1

4313003404001 has 4 divisors (see below), whose sum is σ = 4394380826772. Its totient is φ = 4231625981232.

The previous prime is 4313003403941. The next prime is 4313003404009. The reversal of 4313003404001 is 1004043003134.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3557659902976 + 755343501025 = 1886176^2 + 869105^2 .

It is a cyclic number.

It is not a de Polignac number, because 4313003404001 - 214 = 4313003387617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4313003404009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40688711306 + ... + 40688711411.

It is an arithmetic number, because the mean of its divisors is an integer number (1098595206693).

Almost surely, 24313003404001 is an apocalyptic number.

It is an amenable number.

4313003404001 is a deficient number, since it is larger than the sum of its proper divisors (81377422771).

4313003404001 is an equidigital number, since it uses as much as digits as its factorization.

4313003404001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81377422770.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 4313003404001 its reverse (1004043003134), we get a palindrome (5317046407135).

The spelling of 4313003404001 in words is "four trillion, three hundred thirteen billion, three million, four hundred four thousand, one".

Divisors: 1 53 81377422717 4313003404001