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4313014044001 = 13621195340883
BaseRepresentation
bin111110110000110011101…
…010111000010101100001
3120021022122100211122212221
4332300303222320111201
51031131023043402001
613101212111151041
7623414336324635
oct76606352702541
916238570748787
104313014044001
111413158a95833
12597a83815481
1325393bba54a0
1410ca72a24dc5
15772d0e421a1
hex3ec33ab8561

4313014044001 has 8 divisors (see below), whose sum is σ = 4644859997120. Its totient is φ = 3981178896912.

The previous prime is 4313014043981. The next prime is 4313014044011. The reversal of 4313014044001 is 1004404103134.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4313014044001 - 211 = 4313014041953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4313014044011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1862895 + ... + 3477988.

It is an arithmetic number, because the mean of its divisors is an integer number (580607499640).

Almost surely, 24313014044001 is an apocalyptic number.

It is an amenable number.

4313014044001 is a deficient number, since it is larger than the sum of its proper divisors (331845953119).

4313014044001 is a wasteful number, since it uses less digits than its factorization.

4313014044001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5403015.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4313014044001 its reverse (1004404103134), we get a palindrome (5317418147135).

The spelling of 4313014044001 in words is "four trillion, three hundred thirteen billion, fourteen million, forty-four thousand, one".

Divisors: 1 13 62119 807547 5340883 69431479 331770311077 4313014044001