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431310220241 = 3113913232911
BaseRepresentation
bin1100100011011000001…
…01111010101111010001
31112020021202021100122112
412101230011322233101
524031310404021431
6530050254515105
743106161244645
oct6215405725721
91466252240575
10431310220241
11156a1041427a
126b710b05a95
13318982a9294
1416c3862cc25
15b345580c2b
hex646c17abd1

431310220241 has 4 divisors (see below), whose sum is σ = 445223453184. Its totient is φ = 417396987300.

The previous prime is 431310220193. The next prime is 431310220267. The reversal of 431310220241 is 142022013134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 431310220241 - 230 = 430236478417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (431310220441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6956616425 + ... + 6956616486.

It is an arithmetic number, because the mean of its divisors is an integer number (111305863296).

Almost surely, 2431310220241 is an apocalyptic number.

It is an amenable number.

431310220241 is a deficient number, since it is larger than the sum of its proper divisors (13913232943).

431310220241 is a wasteful number, since it uses less digits than its factorization.

431310220241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13913232942.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 431310220241 its reverse (142022013134), we get a palindrome (573332233375).

The spelling of 431310220241 in words is "four hundred thirty-one billion, three hundred ten million, two hundred twenty thousand, two hundred forty-one".

Divisors: 1 31 13913232911 431310220241