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43131414601601 is a prime number
BaseRepresentation
bin10011100111010010100001…
…01001010101111110000001
312122201022201102221201222022
421303221100221111332001
521123131114114222401
6231422144234451225
712041066443014104
oct1163512051257601
9178638642851868
1043131414601601
1112819a26122007
124a071a7593b15
131b0b376090b51
14a918006b073b
154ebe315a071b
hex273a50a55f81

43131414601601 has 2 divisors, whose sum is σ = 43131414601602. Its totient is φ = 43131414601600.

The previous prime is 43131414601577. The next prime is 43131414601603. The reversal of 43131414601601 is 10610641413134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41826279720976 + 1305134880625 = 6467324^2 + 1142425^2 .

It is a cyclic number.

It is not a de Polignac number, because 43131414601601 - 210 = 43131414600577 is a prime.

Together with 43131414601603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (43131414601603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21565707300800 + 21565707300801.

It is an arithmetic number, because the mean of its divisors is an integer number (21565707300801).

Almost surely, 243131414601601 is an apocalyptic number.

It is an amenable number.

43131414601601 is a deficient number, since it is larger than the sum of its proper divisors (1).

43131414601601 is an equidigital number, since it uses as much as digits as its factorization.

43131414601601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 43131414601601 in words is "forty-three trillion, one hundred thirty-one billion, four hundred fourteen million, six hundred one thousand, six hundred one".