Base | Representation |
---|---|
bin | 111110110000111111100… |
… | …110000111110001111101 |
3 | 120021100011022022201212011 |
4 | 332300333212013301331 |
5 | 1031131430303420013 |
6 | 13101244015411221 |
7 | 623422316062006 |
oct | 76607746076175 |
9 | 16240138281764 |
10 | 4313214123133 |
11 | 1413250a22193 |
12 | 597b1a823b11 |
13 | 2539714897c6 |
14 | 10ca914281ad |
15 | 772e37b4c3d |
hex | 3ec3f987c7d |
4313214123133 has 4 divisors (see below), whose sum is σ = 4313438987968. Its totient is φ = 4312989258300.
The previous prime is 4313214123121. The next prime is 4313214123137. The reversal of 4313214123133 is 3313214123134.
4313214123133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4313214123133 - 29 = 4313214122621 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4313214123095 and 4313214123104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4313214123137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112403643 + ... + 112442008.
It is an arithmetic number, because the mean of its divisors is an integer number (1078359746992).
Almost surely, 24313214123133 is an apocalyptic number.
It is an amenable number.
4313214123133 is a deficient number, since it is larger than the sum of its proper divisors (224864835).
4313214123133 is a wasteful number, since it uses less digits than its factorization.
4313214123133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 224864834.
The product of its digits is 15552, while the sum is 31.
Adding to 4313214123133 its reverse (3313214123134), we get a palindrome (7626428246267).
Subtracting from 4313214123133 its reverse (3313214123134), we obtain a palindrome (999999999999).
The spelling of 4313214123133 in words is "four trillion, three hundred thirteen billion, two hundred fourteen million, one hundred twenty-three thousand, one hundred thirty-three".
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