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43135134033 = 314378378011
BaseRepresentation
bin101000001011000011…
…011110100101010001
311010100011100211212210
4220023003132211101
51201320043242113
631452131342333
73054633406155
oct501303364521
9133304324783
1043135134033
1117325727702
128439a519a9
1340b575c364
142132b0d065
1511c6d706c3
hexa0b0de951

43135134033 has 4 divisors (see below), whose sum is σ = 57513512048. Its totient is φ = 28756756020.

The previous prime is 43135134017. The next prime is 43135134067. The reversal of 43135134033 is 33043153134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43135134033 - 24 = 43135134017 is a prime.

It is a super-3 number, since 3×431351340333 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43135134013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7189189003 + ... + 7189189008.

It is an arithmetic number, because the mean of its divisors is an integer number (14378378012).

Almost surely, 243135134033 is an apocalyptic number.

It is an amenable number.

43135134033 is a deficient number, since it is larger than the sum of its proper divisors (14378378015).

43135134033 is a wasteful number, since it uses less digits than its factorization.

43135134033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14378378014.

The product of its (nonzero) digits is 19440, while the sum is 30.

Adding to 43135134033 its reverse (33043153134), we get a palindrome (76178287167).

The spelling of 43135134033 in words is "forty-three billion, one hundred thirty-five million, one hundred thirty-four thousand, thirty-three".

Divisors: 1 3 14378378011 43135134033