Base | Representation |
---|---|
bin | 1100100011100011000… |
… | …00101001001001000100 |
3 | 1112020112002022010212212 |
4 | 12101301200221021010 |
5 | 24032002141042012 |
6 | 530103303002552 |
7 | 43111343643614 |
oct | 6216140511104 |
9 | 1466462263785 |
10 | 431401112132 |
11 | 156a57754741 |
12 | 6b737439458 |
13 | 318b1081173 |
14 | 16c4672ca44 |
15 | b34d536b22 |
hex | 6471829244 |
431401112132 has 6 divisors (see below), whose sum is σ = 754951946238. Its totient is φ = 215700556064.
The previous prime is 431401112083. The next prime is 431401112173. The reversal of 431401112132 is 231211104134.
It can be written as a sum of positive squares in only one way, i.e., 313741135876 + 117659976256 = 560126^2 + 343016^2 .
It is a super-2 number, since 2×4314011121322 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 431401112098 and 431401112107.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53925139013 + ... + 53925139020.
It is an arithmetic number, because the mean of its divisors is an integer number (125825324373).
Almost surely, 2431401112132 is an apocalyptic number.
It is an amenable number.
431401112132 is a deficient number, since it is larger than the sum of its proper divisors (323550834106).
431401112132 is a wasteful number, since it uses less digits than its factorization.
431401112132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107850278037 (or 107850278035 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 431401112132 its reverse (231211104134), we get a palindrome (662612216266).
The spelling of 431401112132 in words is "four hundred thirty-one billion, four hundred one million, one hundred twelve thousand, one hundred thirty-two".
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