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431401114121 is a prime number
BaseRepresentation
bin1100100011100011000…
…00101001101000001001
31112020112002022020121112
412101301200221220021
524032002141122441
6530103303020105
743111343652455
oct6216140515011
91466462266545
10431401114121
11156a5775618a
126b73743a635
13318b1082043
1416c4672d665
15b34d5374eb
hex6471829a09

431401114121 has 2 divisors, whose sum is σ = 431401114122. Its totient is φ = 431401114120.

The previous prime is 431401114103. The next prime is 431401114141. The reversal of 431401114121 is 121411104134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 388484191225 + 42916922896 = 623285^2 + 207164^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-431401114121 is a prime.

It is a super-2 number, since 2×4314011141212 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (431401114141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215700557060 + 215700557061.

It is an arithmetic number, because the mean of its divisors is an integer number (215700557061).

Almost surely, 2431401114121 is an apocalyptic number.

It is an amenable number.

431401114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

431401114121 is an equidigital number, since it uses as much as digits as its factorization.

431401114121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 431401114121 its reverse (121411104134), we get a palindrome (552812218255).

The spelling of 431401114121 in words is "four hundred thirty-one billion, four hundred one million, one hundred fourteen thousand, one hundred twenty-one".