Base | Representation |
---|---|
bin | 1100100011100100100… |
… | …10100101001001111001 |
3 | 1112020112222221020011212 |
4 | 12101302102211021321 |
5 | 24032014013444001 |
6 | 530104451332505 |
7 | 43111563135455 |
oct | 6216222451171 |
9 | 1466488836155 |
10 | 431414203001 |
11 | 156a64086041 |
12 | 6b73b8b1135 |
13 | 318b39b5842 |
14 | 16c48379665 |
15 | b34e7707bb |
hex | 64724a5279 |
431414203001 has 2 divisors, whose sum is σ = 431414203002. Its totient is φ = 431414203000.
The previous prime is 431414202971. The next prime is 431414203009. The reversal of 431414203001 is 100302414134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 429941178601 + 1473024400 = 655699^2 + 38380^2 .
It is a cyclic number.
It is not a de Polignac number, because 431414203001 - 26 = 431414202937 is a prime.
It is a super-2 number, since 2×4314142030012 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (431414203009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215707101500 + 215707101501.
It is an arithmetic number, because the mean of its divisors is an integer number (215707101501).
Almost surely, 2431414203001 is an apocalyptic number.
It is an amenable number.
431414203001 is a deficient number, since it is larger than the sum of its proper divisors (1).
431414203001 is an equidigital number, since it uses as much as digits as its factorization.
431414203001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 431414203001 its reverse (100302414134), we get a palindrome (531716617135).
The spelling of 431414203001 in words is "four hundred thirty-one billion, four hundred fourteen million, two hundred three thousand, one".
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