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43141440113 is a prime number
BaseRepresentation
bin101000001011011011…
…100010001001110001
311010100121020020012022
4220023123202021301
51201323202040423
631452514441225
73055041122222
oct501333421161
9133317206168
1043141440113
1117329244542
12843bb93215
1340b6b59775
1421338b1249
1511c76b8dc8
hexa0b6e2271

43141440113 has 2 divisors, whose sum is σ = 43141440114. Its totient is φ = 43141440112.

The previous prime is 43141440077. The next prime is 43141440137. The reversal of 43141440113 is 31104414134.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30341459344 + 12799980769 = 174188^2 + 113137^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43141440113 is a prime.

It is a super-2 number, since 2×431414401132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43141490113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570720056 + 21570720057.

It is an arithmetic number, because the mean of its divisors is an integer number (21570720057).

Almost surely, 243141440113 is an apocalyptic number.

It is an amenable number.

43141440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43141440113 is an equidigital number, since it uses as much as digits as its factorization.

43141440113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 43141440113 its reverse (31104414134), we get a palindrome (74245854247).

The spelling of 43141440113 in words is "forty-three billion, one hundred forty-one million, four hundred forty thousand, one hundred thirteen".