Base | Representation |
---|---|
bin | 111110110010000000111… |
… | …101011010111100111011 |
3 | 120021102222201211011010110 |
4 | 332302000331122330323 |
5 | 1031141202023000021 |
6 | 13101544512115403 |
7 | 623461433205633 |
oct | 76620075327473 |
9 | 16242881734113 |
10 | 4314310750011 |
11 | 1413763a43199 |
12 | 598185b35b63 |
13 | 253ab7729052 |
14 | 10cb56d296c3 |
15 | 77359bd1476 |
hex | 3ec80f5af3b |
4314310750011 has 8 divisors (see below), whose sum is σ = 5833434253824. Its totient is φ = 2835697206440.
The previous prime is 4314310750007. The next prime is 4314310750031. The reversal of 4314310750011 is 1100570134134.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4314310750011 - 22 = 4314310750007 is a prime.
It is a super-2 number, since 2×43143107500112 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4314310750031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10127489811 + ... + 10127490236.
It is an arithmetic number, because the mean of its divisors is an integer number (729179281728).
Almost surely, 24314310750011 is an apocalyptic number.
4314310750011 is a deficient number, since it is larger than the sum of its proper divisors (1519123503813).
4314310750011 is a wasteful number, since it uses less digits than its factorization.
4314310750011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20254980121.
The product of its (nonzero) digits is 5040, while the sum is 30.
Adding to 4314310750011 its reverse (1100570134134), we get a palindrome (5414880884145).
The spelling of 4314310750011 in words is "four trillion, three hundred fourteen billion, three hundred ten million, seven hundred fifty thousand, eleven".
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