Base | Representation |
---|---|
bin | 1100100011100110100… |
… | …11001100011101111001 |
3 | 1112020121011210210002002 |
4 | 12101303103030131321 |
5 | 24032032333004431 |
6 | 530110254350345 |
7 | 43112160123212 |
oct | 6216323143571 |
9 | 1466534723062 |
10 | 431431141241 |
11 | 156a726a4a91 |
12 | 6b7454bb3b5 |
13 | 318b7366479 |
14 | 16c4a708409 |
15 | b350eb93cb |
hex | 64734cc779 |
431431141241 has 2 divisors, whose sum is σ = 431431141242. Its totient is φ = 431431141240.
The previous prime is 431431141217. The next prime is 431431141247. The reversal of 431431141241 is 142141134134.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 412447812841 + 18983328400 = 642221^2 + 137780^2 .
It is a cyclic number.
It is not a de Polignac number, because 431431141241 - 218 = 431430879097 is a prime.
It is a super-2 number, since 2×4314311412412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (431431141247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215715570620 + 215715570621.
It is an arithmetic number, because the mean of its divisors is an integer number (215715570621).
Almost surely, 2431431141241 is an apocalyptic number.
It is an amenable number.
431431141241 is a deficient number, since it is larger than the sum of its proper divisors (1).
431431141241 is an equidigital number, since it uses as much as digits as its factorization.
431431141241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4608, while the sum is 29.
Adding to 431431141241 its reverse (142141134134), we get a palindrome (573572275375).
The spelling of 431431141241 in words is "four hundred thirty-one billion, four hundred thirty-one million, one hundred forty-one thousand, two hundred forty-one".
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