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4314324119983 is a prime number
BaseRepresentation
bin111110110010000001110…
…000011011000110101111
3120021110000122222102021121
4332302001300123012233
51031141213433314413
613101550110441411
7623461654642303
oct76620160330657
916243018872247
104314324119983
111413770545259
1259818a503267
13253aba42a787
1410cb58a09d03
157735ae72b8d
hex3ec81c1b1af

4314324119983 has 2 divisors, whose sum is σ = 4314324119984. Its totient is φ = 4314324119982.

The previous prime is 4314324119977. The next prime is 4314324120019. The reversal of 4314324119983 is 3899114234134.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4314324119983 - 213 = 4314324111791 is a prime.

It is a super-2 number, since 2×43143241199832 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4314324119983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4314324119783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157162059991 + 2157162059992.

It is an arithmetic number, because the mean of its divisors is an integer number (2157162059992).

Almost surely, 24314324119983 is an apocalyptic number.

4314324119983 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314324119983 is an equidigital number, since it uses as much as digits as its factorization.

4314324119983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2239488, while the sum is 52.

The spelling of 4314324119983 in words is "four trillion, three hundred fourteen billion, three hundred twenty-four million, one hundred nineteen thousand, nine hundred eighty-three".