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43143464113 is a prime number
BaseRepresentation
bin101000001011100011…
…010000010010110001
311010100202001001121021
4220023203100102301
51201324211322423
631453030055441
73055064252131
oct501343202261
9133322031537
1043143464113
111732a3a7172
1284407aa581
1340b73b7ab9
142133c7aac1
1511c796895d
hexa0b8d04b1

43143464113 has 2 divisors, whose sum is σ = 43143464114. Its totient is φ = 43143464112.

The previous prime is 43143464099. The next prime is 43143464123. The reversal of 43143464113 is 31146434134.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22346363169 + 20797100944 = 149487^2 + 144212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43143464113 is a prime.

It is a super-2 number, since 2×431434641132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43143464123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571732056 + 21571732057.

It is an arithmetic number, because the mean of its divisors is an integer number (21571732057).

Almost surely, 243143464113 is an apocalyptic number.

It is an amenable number.

43143464113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43143464113 is an equidigital number, since it uses as much as digits as its factorization.

43143464113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 34.

Adding to 43143464113 its reverse (31146434134), we get a palindrome (74289898247).

The spelling of 43143464113 in words is "forty-three billion, one hundred forty-three million, four hundred sixty-four thousand, one hundred thirteen".