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4314431130173 is a prime number
BaseRepresentation
bin111110110010001000001…
…000101000101000111101
3120021110022010100002122222
4332302020020220220331
51031141423332131143
613102004452215125
7623464424342333
oct76621010505075
916243263302588
104314431130173
11141381599462a
125981ba30a4a5
13253b06657008
1410cb68d03b53
157736555e768
hex3ec88228a3d

4314431130173 has 2 divisors, whose sum is σ = 4314431130174. Its totient is φ = 4314431130172.

The previous prime is 4314431130167. The next prime is 4314431130239. The reversal of 4314431130173 is 3710311344134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4288432147609 + 25998982564 = 2070853^2 + 161242^2 .

It is a cyclic number.

It is not a de Polignac number, because 4314431130173 - 226 = 4314364021309 is a prime.

It is a super-2 number, since 2×43144311301732 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4314431130133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157215565086 + 2157215565087.

It is an arithmetic number, because the mean of its divisors is an integer number (2157215565087).

Almost surely, 24314431130173 is an apocalyptic number.

It is an amenable number.

4314431130173 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314431130173 is an equidigital number, since it uses as much as digits as its factorization.

4314431130173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 35.

The spelling of 4314431130173 in words is "four trillion, three hundred fourteen billion, four hundred thirty-one million, one hundred thirty thousand, one hundred seventy-three".