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43144324894351 is a prime number
BaseRepresentation
bin10011100111101010100100…
…01010001100111010001111
312122202120001011221120020001
421303311102022030322033
521123334034133104401
6231432121303105131
712042034406465422
oct1163652212147217
9178676034846201
1043144324894351
11128244506a603a
124a097ab1421a7
131b0c6529b3c25
14a922a71679b9
154ec439bd2601
hex273d5228ce8f

43144324894351 has 2 divisors, whose sum is σ = 43144324894352. Its totient is φ = 43144324894350.

The previous prime is 43144324894337. The next prime is 43144324894367. The reversal of 43144324894351 is 15349842344134.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 43144324894351 - 211 = 43144324892303 is a prime.

It is a super-2 number, since 2×431443248943512 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43144324894292 and 43144324894301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43144324894381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21572162447175 + 21572162447176.

It is an arithmetic number, because the mean of its divisors is an integer number (21572162447176).

Almost surely, 243144324894351 is an apocalyptic number.

43144324894351 is a deficient number, since it is larger than the sum of its proper divisors (1).

43144324894351 is an equidigital number, since it uses as much as digits as its factorization.

43144324894351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19906560, while the sum is 55.

The spelling of 43144324894351 in words is "forty-three trillion, one hundred forty-four billion, three hundred twenty-four million, eight hundred ninety-four thousand, three hundred fifty-one".