43152534041 has 2 divisors, whose sum is σ = 43152534042. Its totient is φ = 43152534040.

The previous prime is 43152534017. The next prime is 43152534043. The reversal of 43152534041 is 14043525134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40805616016 + 2346918025 = 202004^2 + 48445^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43152534041 is a prime.

It is a super-3 number, since 3×43152534041³ (a number of 33 digits) contains 333 as substring.

Together with 43152534043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43152533989 and 43152534007.

It is not a weakly prime, because it can be changed into another prime (43152534043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21576267020 + 21576267021.

It is an arithmetic number, because the mean of its divisors is an integer number (21576267021).

Almost surely, 2^43152534041 is an apocalyptic number.

It is an amenable number.

43152534041 is a deficient number, since it is larger than the sum of its proper divisors (1).

43152534041 is an equidigital number, since it uses as much as digits as its factorization.

43152534041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

The spelling of 43152534041 in words is "forty-three billion, one hundred fifty-two million, five hundred thirty-four thousand, forty-one".