Base | Representation |
---|---|
bin | 10011100111111011011001… |
… | …01110111000101101000001 |
3 | 12122210102100220022200001021 |
4 | 21303331230232320231001 |
5 | 21124011040311344441 |
6 | 231440214042505441 |
7 | 12042504335251435 |
oct | 1163755456705501 |
9 | 178712326280037 |
10 | 43153360653121 |
11 | 128282680a0374 |
12 | 4a0b4b1205281 |
13 | 1b104629a4454 |
14 | a928c320a9c5 |
15 | 4ec7b80c43d1 |
hex | 273f6cbb8b41 |
43153360653121 has 12 divisors (see below), whose sum is σ = 45545336383872. Its totient is φ = 40881046954104.
The previous prime is 43153360653113. The next prime is 43153360653163. The reversal of 43153360653121 is 12135606335134.
It is not a de Polignac number, because 43153360653121 - 23 = 43153360653113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43153360153121) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12212296 + ... + 15344278.
It is an arithmetic number, because the mean of its divisors is an integer number (3795444698656).
Almost surely, 243153360653121 is an apocalyptic number.
It is an amenable number.
43153360653121 is a deficient number, since it is larger than the sum of its proper divisors (2391975730751).
43153360653121 is a wasteful number, since it uses less digits than its factorization.
43153360653121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3170188 (or 3170169 counting only the distinct ones).
The product of its (nonzero) digits is 583200, while the sum is 43.
Adding to 43153360653121 its reverse (12135606335134), we get a palindrome (55288966988255).
The spelling of 43153360653121 in words is "forty-three trillion, one hundred fifty-three billion, three hundred sixty million, six hundred fifty-three thousand, one hundred twenty-one".
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