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431664211056341 is a prime number
BaseRepresentation
bin110001000100110001010011…
…1111101100101011011010101
32002121101200210001122222200002
41202021202213331211123111
5423034341301012300331
64130023445000501045
7156631465362033524
oct14211424775453325
92077350701588602
10431664211056341
111155a584475114a
12404b74baa7a785
13156b29b68ba513
1478849331484bb
1534d889b7a49cb
hex18898a7f656d5

431664211056341 has 2 divisors, whose sum is σ = 431664211056342. Its totient is φ = 431664211056340.

The previous prime is 431664211056233. The next prime is 431664211056359. The reversal of 431664211056341 is 143650112466134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 425937982210225 + 5726228846116 = 20638265^2 + 2392954^2 .

It is a cyclic number.

It is not a de Polignac number, because 431664211056341 - 210 = 431664211055317 is a prime.

It is a super-2 number, since 2×4316642110563412 (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431664211056541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215832105528170 + 215832105528171.

It is an arithmetic number, because the mean of its divisors is an integer number (215832105528171).

Almost surely, 2431664211056341 is an apocalyptic number.

It is an amenable number.

431664211056341 is a deficient number, since it is larger than the sum of its proper divisors (1).

431664211056341 is an equidigital number, since it uses as much as digits as its factorization.

431664211056341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 47.

The spelling of 431664211056341 in words is "four hundred thirty-one trillion, six hundred sixty-four billion, two hundred eleven million, fifty-six thousand, three hundred forty-one".