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431664211056497 is a prime number
BaseRepresentation
bin110001000100110001010011…
…1111101100101011101110001
32002121101200210001122222212212
41202021202213331211131301
5423034341301012301442
64130023445000501505
7156631465362034136
oct14211424775453561
92077350701588785
10431664211056497
111155a5844751281
12404b74baa7a895
13156b29b68ba603
14788493314858d
1534d889b7a4a82
hex18898a7f65771

431664211056497 has 2 divisors, whose sum is σ = 431664211056498. Its totient is φ = 431664211056496.

The previous prime is 431664211056493. The next prime is 431664211056503. The reversal of 431664211056497 is 794650112466134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 342322375825936 + 89341835230561 = 18501956^2 + 9452081^2 .

It is a cyclic number.

It is not a de Polignac number, because 431664211056497 - 22 = 431664211056493 is a prime.

It is a super-2 number, since 2×4316642110564972 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (431664211056493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215832105528248 + 215832105528249.

It is an arithmetic number, because the mean of its divisors is an integer number (215832105528249).

Almost surely, 2431664211056497 is an apocalyptic number.

It is an amenable number.

431664211056497 is a deficient number, since it is larger than the sum of its proper divisors (1).

431664211056497 is an equidigital number, since it uses as much as digits as its factorization.

431664211056497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26127360, while the sum is 59.

The spelling of 431664211056497 in words is "four hundred thirty-one trillion, six hundred sixty-four billion, two hundred eleven million, fifty-six thousand, four hundred ninety-seven".