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431664211056503 is a prime number
BaseRepresentation
bin110001000100110001010011…
…1111101100101011101110111
32002121101200210001122222220002
41202021202213331211131313
5423034341301012302003
64130023445000501515
7156631465362034145
oct14211424775453567
92077350701588802
10431664211056503
111155a5844751287
12404b74baa7a89b
13156b29b68ba609
147884933148595
1534d889b7a4a88
hex18898a7f65777

431664211056503 has 2 divisors, whose sum is σ = 431664211056504. Its totient is φ = 431664211056502.

The previous prime is 431664211056497. The next prime is 431664211056541. The reversal of 431664211056503 is 305650112466134.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 431664211056503 - 26 = 431664211056439 is a prime.

It is a super-2 number, since 2×4316642110565032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431664211056553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215832105528251 + 215832105528252.

It is an arithmetic number, because the mean of its divisors is an integer number (215832105528252).

Almost surely, 2431664211056503 is an apocalyptic number.

431664211056503 is a deficient number, since it is larger than the sum of its proper divisors (1).

431664211056503 is an equidigital number, since it uses as much as digits as its factorization.

431664211056503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 47.

The spelling of 431664211056503 in words is "four hundred thirty-one trillion, six hundred sixty-four billion, two hundred eleven million, fifty-six thousand, five hundred three".