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4323011711561 is a prime number
BaseRepresentation
bin111110111010000111100…
…100111101001001001001
3120022021110010012210111122
4332322013210331021021
51031312011444232221
613105544132005025
7624220155153524
oct76720744751111
916267403183448
104323011711561
111417419457404
125999b3a60775
132548732570ca
1410d34073bbbb
15776b89ddeab
hex3ee8793d249

4323011711561 has 2 divisors, whose sum is σ = 4323011711562. Its totient is φ = 4323011711560.

The previous prime is 4323011711539. The next prime is 4323011711621. The reversal of 4323011711561 is 1651171103234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4000524017161 + 322487694400 = 2000131^2 + 567880^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4323011711561 is a prime.

It is a super-2 number, since 2×43230117115612 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4323011711761) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2161505855780 + 2161505855781.

It is an arithmetic number, because the mean of its divisors is an integer number (2161505855781).

Almost surely, 24323011711561 is an apocalyptic number.

It is an amenable number.

4323011711561 is a deficient number, since it is larger than the sum of its proper divisors (1).

4323011711561 is an equidigital number, since it uses as much as digits as its factorization.

4323011711561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

Adding to 4323011711561 its reverse (1651171103234), we get a palindrome (5974182814795).

The spelling of 4323011711561 in words is "four trillion, three hundred twenty-three billion, eleven million, seven hundred eleven thousand, five hundred sixty-one".